pliss kak bantu jawab pake cara pliss
Jawaban:
– Diketahui
x = √16
y = √9
– Ditanya
√( x² + 2xy + y² ) = ...
= √( x² + 2xy + y² )
= √( √16² + 2(√16√9) + √9² )
= √( 16 + 2(√16√9) + √9² )
= √( 16 + 2(√144) + √9² )
= √( 16 + 2(12) + √9² )
= √( 16 + 24 + √9² )
= √( 16 + 24 + 9 )
= √( 40 + 9 )
= √49
= 7 -› B
_ _ _ _ _ _ _ _ _ _ _ _ _
Penjelasan dengan langkah-langkah:
_____________________________
Diketahui:
- x = [tex]\sqrt{16}[/tex]
- y = [tex]\sqrt{9}[/tex]
Ditanya:
- Nilai dari [tex]\sf\sqrt{x^2 + 2xy + y^2}[/tex] = ...?
Jawab:
[tex]\tt \sqrt{x^2 + 2xy + y^2}[/tex]
[tex]\tt = \sqrt{\sqrt{16}^2 + 2\sqrt{16}\sqrt{9} + \sqrt{9}^2}[/tex]
[tex]\tt = \sqrt{16 + 2 \times 4 \times 3 + 9}[/tex]
[tex]\tt = \sqrt{16 + 24 + 9}[/tex]
[tex]\tt = \sqrt{49}[/tex]
[tex]\tt = 7[/tex]
_____________________________
[answer.2.content]
